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Checking if a variable is defined within a script

AbePetrilloAbePetrillo Members
edited January 2012 in Sahi - Open Source
Hi there,

I've tried many variations on this but with no success.

Checking if variable doesn't exist (works): 
  if(!$myVar)
  {
    //do stuff, works!
  }

Checking if variable exists (does not work): 
  if($myVar)
  {
    //do stuff, does not run this code at all
  }

  if(typeof $myVar === "string")
  {
    //do stuff, doesnt work with variables set to a string
  }

  if((typeof $myVar === "string")==true)
  {
    //do stuff, still doesn't work
  }

Given 
$myVar = {street_one: "My street"}

  if($myVar.hasOwnProperty('street_one'))
  {
    //do stuff, still doesn't work
  }

Comments

  • SumitraSumitra Members
    Hi AbePetrillo,

    Here is a sample code:
    var $text = _getText(_link("SSL Manager"));
_alert($text);
if(typeof $text != "undefined")
  {
   _click(_link("SSL Manager"));
  }

    Check if this solves your issue.

    Regards
    Sumitra
  • AbePetrilloAbePetrillo Members
    edited January 2012
    This doesn't seem to work either...

    Actual lines: 
    _log($ee.street_one, "success");
 _log((typeof $ee.street_one), "success");
 if(typeof $ee.street_one != "undefined"){
  _setValue(_textbox("person[addresses][0][street_one]"), $ee.street_one); 
}

    skips the if statement.
    log: 
    my street at 18-Jan-2012 12:31:28
_log("my street", "success"); at 18-Jan-2012 12:31:28
string at 18-Jan-2012 12:31:28
_log((typeof "my street"), "success"); at 18-Jan-2012 12:31:28
  • AbePetrilloAbePetrillo Members
    edited January 2012
    This may be to do with comparing strings. Similiar problem here:

    http://sahi.co.in/forums/viewtopic.php?id=1502

    EDIT:

    Found out what the problem is, I have to put the code to run on a new line otherwise it is skipped, as follows:

    This fails: 
    if(1==1){_alert("success")}

    This works: 
    if(1==1){
  _alert("success");
}
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