Checking if a variable is defined within a script

AbePetrillo

Hi there,

I've tried many variations on this but with no success.

Checking if variable doesn't exist (works):

  if(!$myVar)
  {
    //do stuff, works!
  }

Checking if variable exists (does not work):

  if($myVar)
  {
    //do stuff, does not run this code at all
  }

  if(typeof $myVar === "string")
  {
    //do stuff, doesnt work with variables set to a string
  }

  if((typeof $myVar === "string")==true)
  {
    //do stuff, still doesn't work
  }

Given

$myVar = {street_one: "My street"}

  if($myVar.hasOwnProperty('street_one'))
  {
    //do stuff, still doesn't work
  }

Sumitra

Hi AbePetrillo,

Here is a sample code:

var $text = _getText(_link("SSL Manager"));
_alert($text);
if(typeof $text != "undefined")
  {
   _click(_link("SSL Manager"));
  }

Check if this solves your issue.

Regards
Sumitra

AbePetrillo

This doesn't seem to work either...

Actual lines:

_log($ee.street_one, "success");
 _log((typeof $ee.street_one), "success");
 if(typeof $ee.street_one != "undefined"){
  _setValue(_textbox("person[addresses][0][street_one]"), $ee.street_one); 
}

skips the if statement.
log:

my street at 18-Jan-2012 12:31:28
_log("my street", "success"); at 18-Jan-2012 12:31:28
string at 18-Jan-2012 12:31:28
_log((typeof "my street"), "success"); at 18-Jan-2012 12:31:28

AbePetrillo

This may be to do with comparing strings. Similiar problem here:

http://sahi.co.in/forums/viewtopic.php?id=1502

EDIT:

Found out what the problem is, I have to put the code to run on a new line otherwise it is skipped, as follows:

This fails:

if(1==1){_alert("success")}

This works:

if(1==1){
  _alert("success");
}