Comments

• pankaj.nith Members

  September 2008 edited September 2008

  Hi Stringy,
  
  I am not sure but using variable index in the array might be posing the problem. Try wrapping the entire thing in a function and calling it.
  Try it.. will try using ur loop at my place.
  
  Regards,
  Pankaj.
• pankaj.nith Members

  September 2008

  Hi,
  
  Sorry i forgot to mention that directly assigning the length of the array to a variable won't work.
  Try using _set() for the purpose. Other alternatives are directly using the length like:
  

  for (var $j = 0; $j < $arrPicks.length; $j++) {
     _checkbox("checkbox[" + $arrPicks[$j] + "]").click();
  }
  

  or use a function that returns the length of the array.
  
  Regards,
  Pankaj.
• StringyLow Members

  September 2008

  I tried:
  
  var $len = $arrPicks.length;
  for (var $j = 0; $j < $len; $j++) {
  var $num = clickCheckboxes($j);
  _checkbox("checkedIds[" + $num + "]").click();
  }
  
  function clickCheckboxes($j) {
  return $arrPicks[$j];
  }
  
  and I tried
  
  var $item = 0;
  while($arrPicks.length > 0) {
  $item = $arrPicks.pop();
  _checkbox("checkedIds[" + $item + "]").click();
  }
  
  And I tried using $arrPicks.length.
  
  None of them worked.
  
  One point of interest is that I'm seeing a javascript error saying
  

  _sahi._checkbox("checkedIds[" + $arrPicks[$j] + "]") is null
  

  when I use the FOR loop, like the loop is running into the end of the array instead of paying attention to the loop condition.
• pankaj.nith Members

  September 2008

  Hi,
  
  Try this code:

  var $arrPicks = new Array();   
  var $len;
  _set($len, $arrPicks.length);
  for (var $j = 0; $j < $len; $j++) {
       _click(_checkbox("checkedIds[" + $arrPicks[$j] + "]")); 
  }
  

  ensure the array is populated.
• narayan Administrators

  September 2008

  Pankaj you are right about using _click that way. One further change:
  

  var $arrPicks = new Array();   
  /*
  Populate array here:
  Use 
  _set($arrPicks, getMyCustomBrowserIdsFunction()) 
  if you are populating the array from values on the browser page.
  
  Use 
  $arrPicks = ["a", "b", "c"] 
  if you are not dependent on any browser values to populate this.
  */
  var $len = $arrPicks.length;
  
  
  for (var $j = 0; $j < $len; $j++) {
       _click(_checkbox("checkedIds[" + $arrPicks[$j] + "]")); 
  }
  
• StringyLow Members

  September 2008 edited September 2008

  It got my script to work by loading an array the Sahi way using a temporary array to carry the values:

  var $tempArray = new Array();
  
  <<< $tempArray gets loaded with random values here >>>
  
  var $realArray = new Array();
  _set($realArray, $tempArray.slice());
  
• narayan Administrators

  September 2008

  I will look at this (buggy) behavior. Thanks for highlighting it.
• AbePetrillo Members

  January 2012

  Still buggy in build 2011-05-25
• Sumitra Members

  January 2012

  Hi Abepetrillo,
  
  Are you facing any issue working with 2011-05-25?
  
  There are made bug fixed in the latest version of Sahi. Please try using it.
  
  Regards
  Sumitra