Comments

• globalworming Moderators

  May 2011

  Hi
  
  try to use the _collect API, example here
  it should work as _collect(elementType, name, _in(leftPanel))
  
  regards
  Wormi
• siva Members

  May 2011 edited May 2011

  Dear Wormi,
  
  thanks a lot for your reply
  
  i am new to sahi, i am not getting how to use _collect(elementType, name, _in(leftPanel))
  
  to understand my problem please view this site
  http: // sdeportal.ct.gov/Cedar/WEB/ct_report/DTHome.aspx
  
  here we can see some links in left side like
  
  
  Average Class Size
  CAPT
  CMT
  Discipline
  
  this links are existing under "---_div("Menutagname1_TreeView1")---" div tag
  now if i use "---document.links---" i am getting all the links but i want only the links count and links data which is existing in left side under "---div tag---"
  
  i have tried like this way
  
  _div("Menutagname1_TreeView1").document.links
  and
  var $els = _collect("_link", _div("Menutagname1_TreeView1"));
  
  but it is displaying error
  
  the solution for this in QTP is like this way i have used, it will get only the links count and links data from that specific left side "---div tag---"
  
  QTP: --- Set Links_SubjectArea = Browser("micclass:=Browser").Page("micclass:=Page").WebElement("html id:=Menutagname1_TreeView1").ChildObjects(oDescLink)
  
  now i want the same way which i have shown above in QTP, i want in sahi
  
  please provide me the syntax in sahi to get the links under "---div tag---"
  
  Thanks in advance and thanks a lot for your reply
  
  Regards,
  Siva
• globalworming Moderators

  May 2011

  hi siva
  
  
  _count("_link", "/./", _in(_div("Menutagname1_TreeView1")));
  will return 19, the number of links in the left sidebar
  var $allLinksCollected = _collect("_link", "/./", _in(_div("Menutagname1_TreeView1")));
  should store all link objekts in an array
  
  hope this helps
  
  Reagrds
  Wormi
• siva Members

  May 2011 edited May 2011

  Dear Wormi,
  
  Awesome! this is working fine. thanks a lot
  
  but i got small problem with getting link name of that link object which is stored in array
  
  actually i need the link names to be used again and again when ever i required . so i have storing this values in array and try to retrieve again
  when i try to retrieve the array instead of giving link name it is giving
  
  _link("/./[0]", _in(_div("Menutagname1_TreeView1"))).text
  
  
  i use
  var $allLinksCollected = _collect("_link", "/./", _in(_div("Menutagname1_TreeView1")));
  $allLinksCollected[$i].text to get the link name
  
  
  i have written code like this
  
  var $allLinksCollected = _collect("_link", "/./", _in(_div("Menutagname1_TreeView1")));
  var $arry_SubjArea = [];
  $arry_SubjArea = $allLinksCollected;
  
  for(var $i=0; $i<$allLinksCollected.length; $i++){
  $arry_SubjArea[$i] = $allLinksCollected[$i].text;
  }
  
  for(var $i=0; $i<$arry_SubjArea.length; $i++){
  _debug("

  ---

  "+ $arry_SubjArea[$i] +"

  ---

  ");
  _alert("

  ---

  "+ $arry_SubjArea[$i] +"

  ---

  ");
  }
  
  
  please open the site and run the above code
  
  URL: http: // sdeportal.ct.gov/Cedar/WEB/ct_report/DTHome.aspx
  
  when i use to see the output of _alert(), it is displaying the link names in correct format
  Example: Average Class Size
  
  
  but when i use _debug() instead of _alert() it is not displaying as "--- Average class size---"
  it is displaying as "--- _link("/./[0]", _in(_div("Menutagname1_TreeView1"))).text ---"
  im not getting the link name when i use _debug()
  
  
  why this is displaying differently in _debug() and _alert()
  when i use _alert() it is displaying correctly with link name
  but
  when i use _debug() it is not displaying correctly with link name
  
  Thank you very much for your help
  
  Regards,
  Sivakumar S
• globalworming Moderators

  May 2011

  This might be happening because _debug works in the proxy and and _alert in the browser. Try to use _set when storing browser data
  
  _set($arry_SubjArea[$i], $allLinksCollected[$i].text);
• siva Members

  May 2011

  Dear Wormi,
  
  Tremendous ! its working fine. really great
  
  Thank you very very very much for your help.
  
  
  Regards,
  Sivakumar S
• globalworming Moderators

  May 2011

  np ;-)
• siva Members

  May 2011

  Dear Wormi,
  
  i have small doubt in this line.
  could you please tell me the use of
  
  "/./"
  
  in below line. im not getting what is the use of this
  
  var $allLinksCollected = _collect("_link", "/./", _in(_div("Menutagname1_TreeView1")));
  
  Thank you
  
  
  Regards,
  Sivakumar S
• globalworming Moderators

  May 2011

  the "/./" is the regular expression, which is matched against the link names. "//" wasn't working, I dont know why..
  
  _collect("_link", "/./") says: store all links with a name containing anything in an array. google for JavaScript regular expressions and pattern matching, this may be more usefull than me explaining
• siva Members

  May 2011

  Dear Wormi,
  
  ok now i got it. thanks a lot
  
  
  Regards,
  Sivakumar S