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how to get Json string from http response
smitty1_2
Members
OS: Win7, 64bit
Browser: Firefox 3.6.15
Sahi (Build: 2011-02-13)
Hi,
I'm new to Sahi and to Javascript but I read most of the API doc. I have two different http responses. One is a html site with a table. One is only a JSON String (content type="text/plain") with the same information as in the table.
What I want to do is to see if the results of both reponses are the same. I can access the html easily. But I can't figure out how to get the JSON String in Sahi. I tried to run following code:
I know there's an underscore. It's a p in the actual code. This will only return me null for the $jsonObj. Is my approach right? Any other suggestions?
Thanks in advance
Browser: Firefox 3.6.15
Sahi (Build: 2011-02-13)
Hi,
I'm new to Sahi and to Javascript but I read most of the API doc. I have two different http responses. One is a html site with a table. One is only a JSON String (content type="text/plain") with the same information as in the table.
What I want to do is to see if the results of both reponses are the same. I can access the html easily. But I can't figure out how to get the JSON String in Sahi. I tried to run following code:
<browser>
function javaScriptCode(){
xmlhttp=new XMLHttpRequest();
xmlhttp.open("GET", "htt_://localhost:8080/...", true);
xmlhttp.send();
if (xmlhttp.readyState==4) {
var $json = xmlhttp.responseText;
}
return $json;
}
</browser>
var $jsonObj;
_set($jsonObj, javaScriptCode());
_alert($jsonObj);
I know there's an underscore. It's a p in the actual code. This will only return me null for the $jsonObj. Is my approach right? Any other suggestions?
Thanks in advance
Comments
In the latest version of Sahi (20110314), you could do
var $jsonObj = _readURL("http://localhost:8080/..."
_alert($jsonObj);
Regards,
Narayan
thanks for the fast answer! Now I get this error:
<HTML><HEAD><TITLE>Error</TITLE></HEAD><BODY><H1>Error</H1><HR><!--
warning: Attempt to write out null variable: error
--></BODY></HTML>
But I figured out how to do it. I just put _navigateTo(url); above my javascript call. Then it works fine.
Best regards
Edit: I'm sorry, the database was not running. Now I get an error with a template but that's probably a problem with the Servlet. I'll just stick to my solution.