Comments

• narayan Administrators

  December 2010

  Hi rj412,
  
  Is there a reason why it uses both "Page 2" and "Page 3"?
  
  The right way to do it is like this:

  var $condn;
  _popup("Page 2")._set($condn, _exists(_image("Image.gif")));
  // Note that we have removed the _popup prefix before _exists. 
  if ($condn) {
    PageExistDoSomething();
  } else {
    PageDoesNotExistDoSomethingElse();
  }
  

  
  
  _popup is a marker to execute a particular piece of code on another window. It is to be used only at the start of the command. We are trying to simplify this and make it more intuitive, but currently, you need to use _popup only at the start of the command.
  
  Regards,
  Narayan
• rj412 Members

  December 2010

  our application uses a portal that launches the apps by launching multiple popup windows.
  
  By not having it as prefix as well as condition check, Sahi is confused as to which window to look for.
  From the Portal, I launch 'App2-Page2' , it then automatically launches 'App3-Page3' popup.
  So at this point, I need to do a _isVisible or _exists of an image of 'App3-Page3', if it does not exists, I need to force it to launch...see code below.
  
  
  /* ---- Code

  ---

  */
  launchFromPortal (App2-Page2-Link);
  
  Perform_App2-Page2_operations ();
  //At this point App2-Page2 will automatically launch App3-Page3 due to some other condition
  
  var $condn;
  _popup("App2-Page2")._set($condn, _exists(_popup("App3-Page3)._image("Image.gif")));
  
  if ($condn) {
  App3-Page3_AutomaticLaunch_WORKED();
  } else {
  App3-Page3_AutomaticLaunch_FAILED();
  App3-Page3_ForceLaunch_INSTEAD();
  }
  
  
  I hope this helps.
  Thanks,
  RJ