Comments

• Venky Members

  January 2010

  I just tried this,
  
  var $ar = "http://www.sahi.co.in/demo", "[url]http://www.sahi.co.in/forums[/url]";
  _navigateTo($ar[0][0]);
  _navigateTo($ar[0][1]);
  
  its working fine. Can you tell me what error you are getting in the logs?
• alamoon Members

  January 2010

  it's working fine but $ar has a terminal value, in my code $ar is a variable:
  
  var j = 24 ;
  for(var i = 0; i < 20; i++){
  $linkArray = top.document.links[j];
  j++; j++;
  }
  
  // browse the saved links
  
  _navigateTo($url);
  
  
  //
• alamoon Members

  January 2010

  sorry here the right code:
  var j = 24 ;
  for(var i = 0; i < 20; i++){
  $linkArray = top.document.links[j];
  j++; j++;
  }
  
  // browse the saved links
  $url = $linkArray[0];
  _navigateTo($url);
  //
• Venky Members

  January 2010

  if you declare as,
  var $linkArray = top.document.links[j];
  then $linkArray will be considered as a string and not as an array. so $linkArray[0] returns first character of the string.
  
  Try using it as

  var $linkArray = new Array();
  var j = 24 ;    
  for(var i = 0; i < 20; i++){ 
     $linkArray[i] = top.document.links[j]; 
     j++; j++;
  }
                 
  // browse the saved links
  $url =  $linkArray[0];
  _navigateTo($url);
  

  
  and make sure that url in $linkArray[0] is formatted correctly by alerting it.
• alamoon Members

  January 2010

  i tried it but :-((
  
  by alert the url from $linkArray[0] is formatted correctly.
• Venky Members

  January 2010

  can you paste the url here which is not working?
• narayan Administrators

  January 2010

  Hi alamoon,
  
  To fetch values from the browser, you need to use _set.
  A simple sample script is here:
  

  var $linkArray = new Array();
  for(var $i = 0; $i < 5; $i++){
      _set($href, top.document.links[$i].href);
      $linkArray[$i] = $href;
  
          // There is a bug in Sahi which is preventing the assignment of value to an array variable like this:
          // _set($linkArray[$i], top.document.links[$i].href);
          // The next release should have this fixed.
  }
                 
  // browse the saved links
  var $url =  $linkArray[0];
  _navigateTo($url);
  
• alamoon Members

  January 2010

  i tried it, but nothing :-((
  
  the system seems not accept :
  _set($href, top.document.links[$i].href);
• alamoon Members

  January 2010

  the isn't to fetch the values from a browser but just to navigate to a variableurl.
• alamoon Members

  January 2010

  i get it :-)))))))))))))
  
  var $linkArray = new Array();
  
  // copy the links
  var j = 24 ;
  for(var i = 0; i < 20; i++){
  $linkArray = top.document.links[j];
  j++; j++;
  var $url = $linkArray[0];
  _call(window.open($url, $url ));
  _wait(6000);
  
  }
  //
  it works now, thank you for support.