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How to pass the value of _lastAlert() in the HTML

AdmirerAdmirer Members
edited November -1 in Sahi - Open Source
Hi,

In my application, i have to validate the PopUps so, for that i have written code as follows:

var $actualValue =_lastAlert();

var $expectedValue = "User LoginID is Required";

var $htmlReport = "<html><body><table border='1' colspan='2'><th>Check Point</th><th>Actual Value</th><th>Expected Value</th><th>Status</th>";

if(_condition(_lastAlert() == $expectedValue)){
$htmlReport += "<tr><td>PopUp</td><td>"+$actualValue+"</td><td>"+$expectedValue+"</td><td><b><font color='green'>"+"Pass"+"</font></b></td></tr>";
}

-> In the html page, it's shown as "_sahi._lastAlert()" insteadof "User LoginID is Required".



Thanks in Advance.

Thanks & Regards,
Tulasi
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Comments

  • narayannarayan Administrators
    Hi Tulasi,

    Use
    _set($actualValue, _lastAlert());

    instead of
    var $actualValue =_lastAlert();

    Regards,
    Narayan
  • AdmirerAdmirer Members
    Thanks Narayan.
This discussion has been closed.