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Test to see if Popup Window is available
Mark
Members
I'm having great difficulty establishing whether or not a Popup window exists.
If the popup has not been created there seems to be no Sahi way of checking that it has not been created.
These all fail with the following Error message:
Window/Domain not found: popupNameFromStep=SF-42400000003 for FOA00000001; derivedName=; windowName=; windowTitle=Sahi Start; wasOpened=0; domain=
--Stopped Playback: FAILURE--
And in the log:
_debug(_popup("SF-42400000003 for FOA00000001").exists())
Window/Domain not found: popupNameFromStep=SF-42400000003 for FOA00000001; derivedName=; windowName=; windowTitle=Sahi Start; wasOpened=0; domain= at Jul 27, 2014 11:11:43 AM
Here are the ways I've attempted to check to see if a particular Popup window is available:
var $popupname = "SF-42400000003 for FOA00000001";
_debug($popupname);
var $exists = _popup($popupname).exists();
_debug($exists)
var $exists = _exists(_popup($popupname));
_debug($exists)
var $exists = _condition(_popup($popupname).exists());
_debug($exists)
var $exists = _condition(_exists(_popup($popupname)));
_debug($exists)
var $exists = _popup($popupname).isVisible();
_debug($exists)
var $exists = _isVisible(_popup($popupname));
_debug($exists)
var $exists = _condition(_popup($popupname).isVisible());
_debug($exists)
var $exists = _condition(_isVisible(_popup($popupname)));
_debug($exists)
Also, I've tried all the asserts.
I tried:
onScriptFailure($exception)
onScriptError($exception)
To try and workaround the failure to check if a Popup exists. No success!
Any help = much appreciated!
-Mark.
If the popup has not been created there seems to be no Sahi way of checking that it has not been created.
These all fail with the following Error message:
Window/Domain not found: popupNameFromStep=SF-42400000003 for FOA00000001; derivedName=; windowName=; windowTitle=Sahi Start; wasOpened=0; domain=
--Stopped Playback: FAILURE--
And in the log:
_debug(_popup("SF-42400000003 for FOA00000001").exists())
Window/Domain not found: popupNameFromStep=SF-42400000003 for FOA00000001; derivedName=; windowName=; windowTitle=Sahi Start; wasOpened=0; domain= at Jul 27, 2014 11:11:43 AM
Here are the ways I've attempted to check to see if a particular Popup window is available:
var $popupname = "SF-42400000003 for FOA00000001";
_debug($popupname);
var $exists = _popup($popupname).exists();
_debug($exists)
var $exists = _exists(_popup($popupname));
_debug($exists)
var $exists = _condition(_popup($popupname).exists());
_debug($exists)
var $exists = _condition(_exists(_popup($popupname)));
_debug($exists)
var $exists = _popup($popupname).isVisible();
_debug($exists)
var $exists = _isVisible(_popup($popupname));
_debug($exists)
var $exists = _condition(_popup($popupname).isVisible());
_debug($exists)
var $exists = _condition(_isVisible(_popup($popupname)));
_debug($exists)
Also, I've tried all the asserts.
I tried:
onScriptFailure($exception)
onScriptError($exception)
To try and workaround the failure to check if a Popup exists. No success!
Any help = much appreciated!
-Mark.
Comments
-Mark.
Why don't you implement some kind of try catch stuff?
Sahi is very good in try catch looping.
We had a similar case in which after clicking a Done button, either a popup will come and you need to click on that and then the required page will load.
Otherwise the required page will be loaded directly.
In our JavaScript was checking for something in DB in background.
try for var $popup = _popup("Title of Popup");
if($popup!= null)
do this
else
do that
var $Winexists = _windowExists($popupname, 1000)
_debug($Winexists)