_condition & _popup

DonnaMoores

Pleas help.

I have some text in a cell of a table... I wish to determine which table the text appears is.... I have this working for a non popup window, but when it comes to popup windows, I can't seem to find a solution.

The reason for doing this is that I am writing scripts along side my developers writing code, and every so often they change the layout and all my checks on cells fail!!!!

The code I am using is:

function tableElements($popup, $text, $cell, $row, $col)
{
    var $SearchCell = 999;

    for (var $i=1; $i<99; $i++) 
    {
        if ($popup == null)
        {
            if (_condition(_cell(_table($i), $row, $col) != null))
            {
                if (_condition(_cell(_table($i), $row, $col).className != "DisabledTabRounded"))
                {
                    var $cellText;
                    _set($cellText, _cell(_table($i), $row, $col).innerText);
                    if ($cellText == $text)
                    {
                        $SearchCell = $i;
                        $i = 999;    
                    }
                }

            } 
        }
        else
        {
            $SearchCell = $cell;
            $i = 999;    
        }
    }
    _assertNotEqual(999, $SearchCell, "Element not found in any table displayed");
    return $SearchCell;
}

$popup is the name of the popup window, if I am not using a popup window then I pass in null.
$text is the search string that I am looking for
$cell is used to pass the hardcoded table number in my popup window - this is the parameter I want to stop using
$row is the row I want to look in
$col is the column I want to look in.

Any help on this would be greatly appreciated.

Donna

pankaj.nith

Hi Donna,

In case of a popup, you will need to use _popup("pop name or ID") with the sahi APIs/methods/functions like:

_popup("pop name or ID")._cell(_table($i), $row, $col);

Regards,
Pankaj