How to test the status of a button

Lou10120

Hi all,

In my application, I want to test if a button is enabled or disabled (greyed out).

Could anybody tell me which function should I use ?

Thanks in advance.

Lou10120

StringyLow

How about:

if (_button("Example").disabled == true) {

_alert("The button is disabled");
}


You'll get a lot more mileage out of Sahi if you understand how the HTML DOM works:

http://www.w3schools.com/htmldom/dom_reference.asp
http://www.w3schools.com/jsref/default.asp

Good luck and keep the questions coming!

DonnaMoores

I use the following for testing if a button is enabled or disabled.

function assertButtonEnabled($popup, $name)
{
    if ($popup == null)
    {
            _assertFalse(_button($name).isDisabled);
    }
    else
    {
            _popup($popup)._assertFalse(_button($name).isDisabled);
    }       
}

function assertButtonDisabled($popup, $name, $space)
{
    if ($popup == null)
    {
            _assertTrue(_button($name).isDisabled);
    }
    else
    {
            _popup($popup)._assertTrue(_button($name).isDisabled);
    }       
}

I call the functions like

assertButton("BrowserDetail", "OK");
or
assertButtonDisabled(null, "OK");

StringyLow

I should take my own advice!

I wasn't aware there was a "isDisabled" property.

Thanks Donna!